====== Latex Wiki ====== \frac{3}{4 \pi} + \sqrt{4 \cdot x^2 + 12}\\ \lim_{n \to \infty} \sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6} renders to: \frac{3}{4 \pi} + \sqrt{4 \cdot x^2 + 12}\\ \lim_{n \to \infty} \sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6}