====== Latex Wiki ======
\frac{3}{4 \pi} + \sqrt{4 \cdot x^2 + 12}\\
\lim_{n \to \infty}
\sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6}
renders to:
\frac{3}{4 \pi} + \sqrt{4 \cdot x^2 + 12}\\
\lim_{n \to \infty}
\sum_{k=1}^n \frac{1}{k^2} = \frac{\pi^2}{6}